Father is aged three times more than his son Ali’s. After 8 years, he would be two and a half times of Ali’s age. After further 8 years, how many times would he be of Ali’s age?

Father is aged three times more than his son Ali’s. After 8 years, he would be two and a half times of Ali’s age. After further 8 years, how many times would he be of Ali’s age?

A. 2 times

B. 2.5 times

C. 3.5 times

D. 3 times

Solution:

Explanation:
Let Ali’s present age be x years. Then, father’s present age =(x + 3x) years = 4x years.
(4x + 8) =
5
—–(x + 8)
2

8x + 16 = 5x + 40
3x = 24
x = 8.
Hence, required ratio =48
(4x + 16)=                      24

48/24= 2